what is the dimension of a rectangle if the perimeter is 198

Answer:Length = 49.5 unit and width = 49.5 unit Step-by-step explanation:Given as , Perimeter of rectangle = 198 unitso ,as Perimeter of rectangle = 2× ( Length + width)Or,                                   198 = 2 ×  (Length + width)Or,                                   [tex]\frac{198}{2}[/tex] = length + widthSo, length + width = 99 unitNow to make area maximumLength × width = maximum Or, (99 - width ) × width = maximum       99 Width - width² = maximum                              Let width = WNow differentiate both side with respect to WD(99W - W²)[tex]\frac{D(99w - w^2)}{Dw}[/tex] = 0         as, constant diff is 0So, 99 - 2w = 0Or, w = [tex]\frac{99}{2}[/tex]Or, w = 49.5 unit    and L = 99- 4905 = 49.5 unit      Answer